Roshel bought some bracelets and necklaces for her friends. The price of each bracelet was $4.70 while the price of each necklace was $11.50. For every 7 necklaces bought, she was given one such bracelet for free. After receiving the free bracelets, the number of bracelets was
13 of the number of necklaces bought. If Roshel paid a total of $1301.50, how much more did she pay for the necklaces than the bracelets?
Necklaces |
Bracelets |
3x7 |
1x7 |
Bought |
Free |
Bought |
7x3 |
1x3 |
|
21 u |
3 u |
4 u |
|
Necklaces |
Bracelets |
|
Bought |
Free |
Bought |
Number |
21 u |
3 u |
4 u |
Value |
$11.50 |
0 |
$4.70 |
Total value |
241.5 u |
0 |
18.8 u |
The number of necklaces bought is the repeated identity. Make the number of necklaces bought the same. LCM of 3 and 7 is 21.
Cost of the bought necklaces
= 21 u x 11.50
= 241.5 u
Cost of the bought bracelets
= 4 u x 4.70
= 18.8 u
Total cost of the bought items
= 241.5 u + 18.8 u
= 260.3 u
260.3 u = 1301.50
1 u = 1301.50 ÷ 260.30 = 5
Amount that she paid more for the necklaces than the bracelets
= 241.5 u - 18.8 u
= 222.7 u
= 222.7 x 5
= $1113.50
Answer(s): $1113.50