Hazel bought some bracelets and necklaces for her friends. The price of each bracelet was $3.10 while the price of each necklace was $14.30. For every 5 necklaces bought, she was given one such bracelet for free. After receiving the free bracelets, the number of bracelets was
13 of the number of necklaces bought. If Hazel paid a total of $662.10, how much more did she pay for the necklaces than the bracelets?
Necklaces |
Bracelets |
3x5 |
1x5 |
Bought |
Free |
Bought |
5x3 |
1x3 |
|
15 u |
3 u |
2 u |
|
Necklaces |
Bracelets |
|
Bought |
Free |
Bought |
Number |
15 u |
3 u |
2 u |
Value |
$14.30 |
0 |
$3.10 |
Total value |
214.5 u |
0 |
6.2 u |
The number of necklaces bought is the repeated identity. Make the number of necklaces bought the same. LCM of 3 and 5 is 15.
Cost of the bought necklaces
= 15 u x 14.30
= 214.5 u
Cost of the bought bracelets
= 2 u x 3.10
= 6.2 u
Total cost of the bought items
= 214.5 u + 6.2 u
= 220.7 u
220.7 u = 662.10
1 u = 662.10 ÷ 220.70 = 3
Amount that she paid more for the necklaces than the bracelets
= 214.5 u - 6.2 u
= 208.3 u
= 208.3 x 3
= $624.90
Answer(s): $624.90