Nora bought some necklaces and rings for her friends. The price of each necklace was $4.90 while the price of each ring was $13.30. For every 8 rings bought, she was given one such necklace for free. After receiving the free necklaces, the number of necklaces was ¹₃ of the number of rings bought. If Nora paid a total of $3093.30, how much more did she pay for the rings than the necklaces?

Rings	Necklaces
3x8	1x8
Bought	Free	Bought
8x3	1x3
24 u	3 u	5 u

	Rings	Necklaces
	Bought	Free	Bought
Number	24 u	3 u	5 u
Value	$13.30	0	$4.90
Total value	319.2 u	0	24.5 u

The number of rings bought is the repeated identity. Make the number of rings bought the same.  LCM of 3 and 8 is 24.

Cost of the bought rings
= 24 u x 13.30
= 319.2 u

Cost of the bought necklaces
= 5 u x 4.90  
= 24.5 u

Total cost of the bought items
= 319.2 u + 24.5 u
= 343.7 u

343.7 u = 3093.30

1 u = 3093.30 ÷ 343.70 = 9

Amount that she paid more for the rings than the necklaces
= 319.2 u - 24.5 u 
= 294.7 u
= 294.7 x 9
= $2652.30

Answer(s): $2652.30