Tiffany bought some bracelets and necklaces for her friends. The price of each bracelet was $4.10 while the price of each necklace was $11.70. For every 8 necklaces bought, she was given one such bracelet for free. After receiving the free bracelets, the number of bracelets was ¹₃ of the number of necklaces bought. If Tiffany paid a total of $1205.20, how much more did she pay for the necklaces than the bracelets?

Necklaces	Bracelets
3x8	1x8
Bought	Free	Bought
8x3	1x3
24 u	3 u	5 u

	Necklaces	Bracelets
	Bought	Free	Bought
Number	24 u	3 u	5 u
Value	$11.70	0	$4.10
Total value	280.8 u	0	20.5 u

The number of necklaces bought is the repeated identity. Make the number of necklaces bought the same.  LCM of 3 and 8 is 24.

Cost of the bought necklaces
= 24 u x 11.70
= 280.8 u

Cost of the bought bracelets
= 5 u x 4.10  
= 20.5 u

Total cost of the bought items
= 280.8 u + 20.5 u
= 301.3 u

301.3 u = 1205.20

1 u = 1205.20 ÷ 301.30 = 4

Amount that she paid more for the necklaces than the bracelets
= 280.8 u - 20.5 u 
= 260.3 u
= 260.3 x 4
= $1041.20

Answer(s): $1041.20