Opal bought some bracelets and necklaces for her friends. The price of each bracelet was $3.40 while the price of each necklace was $13.70. For every 7 necklaces bought, she was given one such bracelet for free. After receiving the free bracelets, the number of bracelets was ¹₄ of the number of necklaces bought. If Opal paid a total of $4331.80, how much more did she pay for the necklaces than the bracelets?

Necklaces	Bracelets
4x7	1x7
Bought	Free	Bought
7x4	1x4
28 u	4 u	3 u

	Necklaces	Bracelets
	Bought	Free	Bought
Number	28 u	4 u	3 u
Value	$13.70	0	$3.40
Total value	383.6 u	0	10.2 u

The number of necklaces bought is the repeated identity. Make the number of necklaces bought the same.  LCM of 4 and 7 is 28.

Cost of the bought necklaces
= 28 u x 13.70
= 383.6 u

Cost of the bought bracelets
= 3 u x 3.40  
= 10.2 u

Total cost of the bought items
= 383.6 u + 10.2 u
= 393.8 u

393.8 u = 4331.80

1 u = 4331.80 ÷ 393.80 = 11

Amount that she paid more for the necklaces than the bracelets
= 383.6 u - 10.2 u 
= 373.4 u
= 373.4 x 11
= $4107.40

Answer(s): $4107.40