Joelle bought some bracelets and necklaces for her friends. The price of each bracelet was $4.20 while the price of each necklace was $12.70. For every 5 necklaces bought, she was given one such bracelet for free. After receiving the free bracelets, the number of bracelets was
13 of the number of necklaces bought. If Joelle paid a total of $1790.10, how much more did she pay for the necklaces than the bracelets?
Necklaces |
Bracelets |
3x5 |
1x5 |
Bought |
Free |
Bought |
5x3 |
1x3 |
|
15 u |
3 u |
2 u |
|
Necklaces |
Bracelets |
|
Bought |
Free |
Bought |
Number |
15 u |
3 u |
2 u |
Value |
$12.70 |
0 |
$4.20 |
Total value |
190.5 u |
0 |
8.4 u |
The number of necklaces bought is the repeated identity. Make the number of necklaces bought the same. LCM of 3 and 5 is 15.
Cost of the bought necklaces
= 15 u x 12.70
= 190.5 u
Cost of the bought bracelets
= 2 u x 4.20
= 8.4 u
Total cost of the bought items
= 190.5 u + 8.4 u
= 198.9 u
198.9 u = 1790.10
1 u = 1790.10 ÷ 198.90 = 9
Amount that she paid more for the necklaces than the bracelets
= 190.5 u - 8.4 u
= 182.1 u
= 182.1 x 9
= $1638.90
Answer(s): $1638.90