Xandra bought some rings and necklaces for her friends. The price of each ring was $2.30 while the price of each necklace was $12.90. For every 7 necklaces bought, she was given one such ring for free. After receiving the free rings, the number of rings was ¹₄ of the number of necklaces bought. If Xandra paid a total of $1472.40, how much more did she pay for the necklaces than the rings?

Necklaces	Rings
4x7	1x7
Bought	Free	Bought
7x4	1x4
28 u	4 u	3 u

	Necklaces	Rings
	Bought	Free	Bought
Number	28 u	4 u	3 u
Value	$12.90	0	$2.30
Total value	361.2 u	0	6.9 u

The number of necklaces bought is the repeated identity. Make the number of necklaces bought the same.  LCM of 4 and 7 is 28.

Cost of the bought necklaces
= 28 u x 12.90
= 361.2 u

Cost of the bought rings
= 3 u x 2.30  
= 6.9 u

Total cost of the bought items
= 361.2 u + 6.9 u
= 368.1 u

368.1 u = 1472.40

1 u = 1472.40 ÷ 368.10 = 4

Amount that she paid more for the necklaces than the rings
= 361.2 u - 6.9 u 
= 354.3 u
= 354.3 x 4
= $1417.20

Answer(s): $1417.20