Shiyun bought some necklaces and rings for her friends. The price of each necklace was $4.10 while the price of each ring was $11.30. For every 7 rings bought, she was given one such necklace for free. After receiving the free necklaces, the number of necklaces was ¹₅ of the number of rings bought. If Shiyun paid a total of $4440.70, how much more did she pay for the rings than the necklaces?

Rings	Necklaces
5x7	1x7
Bought	Free	Bought
7x5	1x5
35 u	5 u	2 u

	Rings	Necklaces
	Bought	Free	Bought
Number	35 u	5 u	2 u
Value	$11.30	0	$4.10
Total value	395.5 u	0	8.2 u

The number of rings bought is the repeated identity. Make the number of rings bought the same.  LCM of 5 and 7 is 35.

Cost of the bought rings
= 35 u x 11.30
= 395.5 u

Cost of the bought necklaces
= 2 u x 4.10  
= 8.2 u

Total cost of the bought items
= 395.5 u + 8.2 u
= 403.7 u

403.7 u = 4440.70

1 u = 4440.70 ÷ 403.70 = 11

Amount that she paid more for the rings than the necklaces
= 395.5 u - 8.2 u 
= 387.3 u
= 387.3 x 11
= $4260.30

Answer(s): $4260.30