Gem bought some necklaces and rings for her friends. The price of each necklace was $3.30 while the price of each ring was $14.30. For every 7 rings bought, she was given one such necklace for free. After receiving the free necklaces, the number of necklaces was
15 of the number of rings bought. If Gem paid a total of $6085.20, how much more did she pay for the rings than the necklaces?
Rings |
Necklaces |
5x7 |
1x7 |
Bought |
Free |
Bought |
7x5 |
1x5 |
|
35 u |
5 u |
2 u |
|
Rings |
Necklaces |
|
Bought |
Free |
Bought |
Number |
35 u |
5 u |
2 u |
Value |
$14.30 |
0 |
$3.30 |
Total value |
500.5 u |
0 |
6.6 u |
The number of rings bought is the repeated identity. Make the number of rings bought the same. LCM of 5 and 7 is 35.
Cost of the bought rings
= 35 u x 14.30
= 500.5 u
Cost of the bought necklaces
= 2 u x 3.30
= 6.6 u
Total cost of the bought items
= 500.5 u + 6.6 u
= 507.1 u
507.1 u = 6085.20
1 u = 6085.20 ÷ 507.10 = 12
Amount that she paid more for the rings than the necklaces
= 500.5 u - 6.6 u
= 493.9 u
= 493.9 x 12
= $5926.80
Answer(s): $5926.80