Dana bought some rings and necklaces for her friends. The price of each ring was $4.70 while the price of each necklace was $11.90. For every 8 necklaces bought, she was given one such ring for free. After receiving the free rings, the number of rings was ¹₃ of the number of necklaces bought. If Dana paid a total of $927.30, how much more did she pay for the necklaces than the rings?

Necklaces	Rings
3x8	1x8
Bought	Free	Bought
8x3	1x3
24 u	3 u	5 u

	Necklaces	Rings
	Bought	Free	Bought
Number	24 u	3 u	5 u
Value	$11.90	0	$4.70
Total value	285.6 u	0	23.5 u

The number of necklaces bought is the repeated identity. Make the number of necklaces bought the same.  LCM of 3 and 8 is 24.

Cost of the bought necklaces
= 24 u x 11.90
= 285.6 u

Cost of the bought rings
= 5 u x 4.70  
= 23.5 u

Total cost of the bought items
= 285.6 u + 23.5 u
= 309.1 u

309.1 u = 927.30

1 u = 927.30 ÷ 309.10 = 3

Amount that she paid more for the necklaces than the rings
= 285.6 u - 23.5 u 
= 262.1 u
= 262.1 x 3
= $786.30

Answer(s): $786.30