Kathy bought some rings and necklaces for her friends. The price of each ring was $4.30 while the price of each necklace was $11.80. For every 8 necklaces bought, she was given one such ring for free. After receiving the free rings, the number of rings was ¹₃ of the number of necklaces bought. If Kathy paid a total of $2437.60, how much more did she pay for the necklaces than the rings?

Necklaces	Rings
3x8	1x8
Bought	Free	Bought
8x3	1x3
24 u	3 u	5 u

	Necklaces	Rings
	Bought	Free	Bought
Number	24 u	3 u	5 u
Value	$11.80	0	$4.30
Total value	283.2 u	0	21.5 u

The number of necklaces bought is the repeated identity. Make the number of necklaces bought the same.  LCM of 3 and 8 is 24.

Cost of the bought necklaces
= 24 u x 11.80
= 283.2 u

Cost of the bought rings
= 5 u x 4.30  
= 21.5 u

Total cost of the bought items
= 283.2 u + 21.5 u
= 304.7 u

304.7 u = 2437.60

1 u = 2437.60 ÷ 304.70 = 8

Amount that she paid more for the necklaces than the rings
= 283.2 u - 21.5 u 
= 261.7 u
= 261.7 x 8
= $2093.60

Answer(s): $2093.60