Mary bought some bracelets and necklaces for her friends. The price of each bracelet was $3.50 while the price of each necklace was $13.60. For every 8 necklaces bought, she was given one such bracelet for free. After receiving the free bracelets, the number of bracelets was
13 of the number of necklaces bought. If Mary paid a total of $3782.90, how much more did she pay for the necklaces than the bracelets?
Necklaces |
Bracelets |
3x8 |
1x8 |
Bought |
Free |
Bought |
8x3 |
1x3 |
|
24 u |
3 u |
5 u |
|
Necklaces |
Bracelets |
|
Bought |
Free |
Bought |
Number |
24 u |
3 u |
5 u |
Value |
$13.60 |
0 |
$3.50 |
Total value |
326.4 u |
0 |
17.5 u |
The number of necklaces bought is the repeated identity. Make the number of necklaces bought the same. LCM of 3 and 8 is 24.
Cost of the bought necklaces
= 24 u x 13.60
= 326.4 u
Cost of the bought bracelets
= 5 u x 3.50
= 17.5 u
Total cost of the bought items
= 326.4 u + 17.5 u
= 343.9 u
343.9 u = 3782.90
1 u = 3782.90 ÷ 343.90 = 11
Amount that she paid more for the necklaces than the bracelets
= 326.4 u - 17.5 u
= 308.9 u
= 308.9 x 11
= $3397.90
Answer(s): $3397.90