Linda bought some necklaces and rings for her friends. The price of each necklace was $2.40 while the price of each ring was $14.10. For every 5 rings bought, she was given one such necklace for free. After receiving the free necklaces, the number of necklaces was ¹₃ of the number of rings bought. If Linda paid a total of $865.20, how much more did she pay for the rings than the necklaces?

Rings	Necklaces
3x5	1x5
Bought	Free	Bought
5x3	1x3
15 u	3 u	2 u

	Rings	Necklaces
	Bought	Free	Bought
Number	15 u	3 u	2 u
Value	$14.10	0	$2.40
Total value	211.5 u	0	4.8 u

The number of rings bought is the repeated identity. Make the number of rings bought the same.  LCM of 3 and 5 is 15.

Cost of the bought rings
= 15 u x 14.10
= 211.5 u

Cost of the bought necklaces
= 2 u x 2.40  
= 4.8 u

Total cost of the bought items
= 211.5 u + 4.8 u
= 216.3 u

216.3 u = 865.20

1 u = 865.20 ÷ 216.30 = 4

Amount that she paid more for the rings than the necklaces
= 211.5 u - 4.8 u 
= 206.7 u
= 206.7 x 4
= $826.80

Answer(s): $826.80