Tiffany bought some bracelets and rings for her friends. The price of each bracelet was $3.90 while the price of each ring was $13.20. For every 8 rings bought, she was given one such bracelet for free. After receiving the free bracelets, the number of bracelets was
13 of the number of rings bought. If Tiffany paid a total of $2354.10, how much more did she pay for the rings than the bracelets?
Rings |
Bracelets |
3x8 |
1x8 |
Bought |
Free |
Bought |
8x3 |
1x3 |
|
24 u |
3 u |
5 u |
|
Rings |
Bracelets |
|
Bought |
Free |
Bought |
Number |
24 u |
3 u |
5 u |
Value |
$13.20 |
0 |
$3.90 |
Total value |
316.8 u |
0 |
19.5 u |
The number of rings bought is the repeated identity. Make the number of rings bought the same. LCM of 3 and 8 is 24.
Cost of the bought rings
= 24 u x 13.20
= 316.8 u
Cost of the bought bracelets
= 5 u x 3.90
= 19.5 u
Total cost of the bought items
= 316.8 u + 19.5 u
= 336.3 u
336.3 u = 2354.10
1 u = 2354.10 ÷ 336.30 = 7
Amount that she paid more for the rings than the bracelets
= 316.8 u - 19.5 u
= 297.3 u
= 297.3 x 7
= $2081.10
Answer(s): $2081.10