Hazel bought some necklaces and bracelets for her friends. The price of each necklace was $4.10 while the price of each bracelet was $11.30. For every 7 bracelets bought, she was given one such necklace for free. After receiving the free necklaces, the number of necklaces was ¹₄ of the number of bracelets bought. If Hazel paid a total of $2629.60, how much more did she pay for the bracelets than the necklaces?

Bracelets	Necklaces
4x7	1x7
Bought	Free	Bought
7x4	1x4
28 u	4 u	3 u

	Bracelets	Necklaces
	Bought	Free	Bought
Number	28 u	4 u	3 u
Value	$11.30	0	$4.10
Total value	316.4 u	0	12.3 u

The number of bracelets bought is the repeated identity. Make the number of bracelets bought the same.  LCM of 4 and 7 is 28.

Cost of the bought bracelets
= 28 u x 11.30
= 316.4 u

Cost of the bought necklaces
= 3 u x 4.10  
= 12.3 u

Total cost of the bought items
= 316.4 u + 12.3 u
= 328.7 u

328.7 u = 2629.60

1 u = 2629.60 ÷ 328.70 = 8

Amount that she paid more for the bracelets than the necklaces
= 316.4 u - 12.3 u 
= 304.1 u
= 304.1 x 8
= $2432.80

Answer(s): $2432.80