Jen bought some rings and necklaces for her friends. The price of each ring was $4.30 while the price of each necklace was $13.90. For every 8 necklaces bought, she was given one such ring for free. After receiving the free rings, the number of rings was
13 of the number of necklaces bought. If Jen paid a total of $3906.10, how much more did she pay for the necklaces than the rings?
Necklaces |
Rings |
3x8 |
1x8 |
Bought |
Free |
Bought |
8x3 |
1x3 |
|
24 u |
3 u |
5 u |
|
Necklaces |
Rings |
|
Bought |
Free |
Bought |
Number |
24 u |
3 u |
5 u |
Value |
$13.90 |
0 |
$4.30 |
Total value |
333.6 u |
0 |
21.5 u |
The number of necklaces bought is the repeated identity. Make the number of necklaces bought the same. LCM of 3 and 8 is 24.
Cost of the bought necklaces
= 24 u x 13.90
= 333.6 u
Cost of the bought rings
= 5 u x 4.30
= 21.5 u
Total cost of the bought items
= 333.6 u + 21.5 u
= 355.1 u
355.1 u = 3906.10
1 u = 3906.10 ÷ 355.10 = 11
Amount that she paid more for the necklaces than the rings
= 333.6 u - 21.5 u
= 312.1 u
= 312.1 x 11
= $3433.10
Answer(s): $3433.10