Shiyun bought some bracelets and necklaces for her friends. The price of each bracelet was $4.50 while the price of each necklace was $10.60. For every 7 necklaces bought, she was given one such bracelet for free. After receiving the free bracelets, the number of bracelets was
14 of the number of necklaces bought. If Shiyun paid a total of $3413.30, how much more did she pay for the necklaces than the bracelets?
Necklaces |
Bracelets |
4x7 |
1x7 |
Bought |
Free |
Bought |
7x4 |
1x4 |
|
28 u |
4 u |
3 u |
|
Necklaces |
Bracelets |
|
Bought |
Free |
Bought |
Number |
28 u |
4 u |
3 u |
Value |
$10.60 |
0 |
$4.50 |
Total value |
296.8 u |
0 |
13.5 u |
The number of necklaces bought is the repeated identity. Make the number of necklaces bought the same. LCM of 4 and 7 is 28.
Cost of the bought necklaces
= 28 u x 10.60
= 296.8 u
Cost of the bought bracelets
= 3 u x 4.50
= 13.5 u
Total cost of the bought items
= 296.8 u + 13.5 u
= 310.3 u
310.3 u = 3413.30
1 u = 3413.30 ÷ 310.30 = 11
Amount that she paid more for the necklaces than the bracelets
= 296.8 u - 13.5 u
= 283.3 u
= 283.3 x 11
= $3116.30
Answer(s): $3116.30