Usha bought some necklaces and rings for her friends. The price of each necklace was $4.50 while the price of each ring was $11.80. For every 8 rings bought, she was given one such necklace for free. After receiving the free necklaces, the number of necklaces was ¹₃ of the number of rings bought. If Usha paid a total of $1834.20, how much more did she pay for the rings than the necklaces?

Rings	Necklaces
3x8	1x8
Bought	Free	Bought
8x3	1x3
24 u	3 u	5 u

	Rings	Necklaces
	Bought	Free	Bought
Number	24 u	3 u	5 u
Value	$11.80	0	$4.50
Total value	283.2 u	0	22.5 u

The number of rings bought is the repeated identity. Make the number of rings bought the same.  LCM of 3 and 8 is 24.

Cost of the bought rings
= 24 u x 11.80
= 283.2 u

Cost of the bought necklaces
= 5 u x 4.50  
= 22.5 u

Total cost of the bought items
= 283.2 u + 22.5 u
= 305.7 u

305.7 u = 1834.20

1 u = 1834.20 ÷ 305.70 = 6

Amount that she paid more for the rings than the necklaces
= 283.2 u - 22.5 u 
= 260.7 u
= 260.7 x 6
= $1564.20

Answer(s): $1564.20