Jen bought some necklaces and bracelets for her friends. The price of each necklace was $4.90 while the price of each bracelet was $11.40. For every 8 bracelets bought, she was given one such necklace for free. After receiving the free necklaces, the number of necklaces was
13 of the number of bracelets bought. If Jen paid a total of $2682.90, how much more did she pay for the bracelets than the necklaces?
Bracelets |
Necklaces |
3x8 |
1x8 |
Bought |
Free |
Bought |
8x3 |
1x3 |
|
24 u |
3 u |
5 u |
|
Bracelets |
Necklaces |
|
Bought |
Free |
Bought |
Number |
24 u |
3 u |
5 u |
Value |
$11.40 |
0 |
$4.90 |
Total value |
273.6 u |
0 |
24.5 u |
The number of bracelets bought is the repeated identity. Make the number of bracelets bought the same. LCM of 3 and 8 is 24.
Cost of the bought bracelets
= 24 u x 11.40
= 273.6 u
Cost of the bought necklaces
= 5 u x 4.90
= 24.5 u
Total cost of the bought items
= 273.6 u + 24.5 u
= 298.1 u
298.1 u = 2682.90
1 u = 2682.90 ÷ 298.10 = 9
Amount that she paid more for the bracelets than the necklaces
= 273.6 u - 24.5 u
= 249.1 u
= 249.1 x 9
= $2241.90
Answer(s): $2241.90