Linda had an equal number of limes and plums at first. She sold half of the plums and bought another 90 limes. In the end, she had four times as many limes as plums. Find the number of plums she had at first.
| |
Plums |
Limes |
| Before |
2 u |
4 u - 90 |
| Change |
- 1 u |
+ 90 |
| After |
1 u |
4 u |
The number of limes and plums at first is the same.
4 u - 90 = 2 u
4 u - 2 u = 90
2 u = 90
1 u = 90 ÷ 2 = 45
Number of plums that she had at first
= 2 u
= 2 x 45
= 90
Answer(s): 90
