Kimberly had an equal number of mandarin oranges and oranges at first. She sold one-quarter of the oranges and bought another 80 mandarin oranges. In the end, she had thrice as many mandarin oranges as oranges. Find the number of oranges she had at first.
| |
Oranges |
Mandarin Oranges |
| Before |
4 u |
9 u - 80 |
| Change |
- 1 u |
+ 80 |
| After |
3 u |
9 u |
The number of mandarin oranges and oranges at first is the same.
9 u - 80 = 4 u
9 u - 4 u = 80
5 u = 80
1 u = 80 ÷ 5 = 16
Number of oranges that she had at first
= 4 u
= 4 x 16
= 64
Answer(s): 64
