Sabrina had an equal number of grapefruits and limes at first. She sold one-quarter of the limes and bought another 80 grapefruits. In the end, she had four times as many grapefruits as limes. Find the number of limes she had at first.
| |
Limes |
Grapefruits |
| Before |
4 u |
12 u - 80 |
| Change |
- 1 u |
+ 80 |
| After |
3 u |
12 u |
The number of grapefruits and limes at first is the same.
12 u - 80 = 4 u
12 u - 4 u = 80
8 u = 80
1 u = 80 ÷ 8 = 10
Number of limes that she had at first
= 4 u
= 4 x 10
= 40
Answer(s): 40
