Sarah had an equal number of apricots and papayas at first. She sold half of the papayas and bought another 92 apricots. In the end, she had four times as many apricots as papayas. Find the number of papayas she had at first.
| |
Papayas |
Apricots |
| Before |
2 u |
4 u - 92 |
| Change |
- 1 u |
+ 92 |
| After |
1 u |
4 u |
The number of apricots and papayas at first is the same.
4 u - 92 = 2 u
4 u - 2 u = 92
2 u = 92
1 u = 92 ÷ 2 = 46
Number of papayas that she had at first
= 2 u
= 2 x 46
= 92
Answer(s): 92
