Irene had an equal number of limes and papayas at first. She sold one-quarter of the papayas and bought another 70 limes. In the end, she had twice as many limes as papayas. Find the number of papayas she had at first.
| |
Papayas |
Limes |
| Before |
4 u |
6 u - 70 |
| Change |
- 1 u |
+ 70 |
| After |
3 u |
6 u |
The number of limes and papayas at first is the same.
6 u - 70 = 4 u
6 u - 4 u = 70
2 u = 70
1 u = 70 ÷ 2 = 35
Number of papayas that she had at first
= 4 u
= 4 x 35
= 140
Answer(s): 140
