Gem had an equal number of guavas and papayas at first. She sold one-quarter of the papayas and bought another 56 guavas. In the end, she had four times as many guavas as papayas. Find the number of papayas she had at first.
| |
Papayas |
Guavas |
| Before |
4 u |
12 u - 56 |
| Change |
- 1 u |
+ 56 |
| After |
3 u |
12 u |
The number of guavas and papayas at first is the same.
12 u - 56 = 4 u
12 u - 4 u = 56
8 u = 56
1 u = 56 ÷ 8 = 7
Number of papayas that she had at first
= 4 u
= 4 x 7
= 28
Answer(s): 28
