Jean had an equal number of peaches and pomegranates at first. She sold one-third of the pomegranates and bought another 45 peaches. In the end, she had thrice as many peaches as pomegranates. Find the number of pomegranates she had at first.
| |
Pomegranates |
Peaches |
| Before |
3 u |
6 u - 45 |
| Change |
- 1 u |
+ 45 |
| After |
2 u |
6 u |
The number of peaches and pomegranates at first is the same.
6 u - 45 = 3 u
6 u - 3 u = 45
3 u = 45
1 u = 45 ÷ 3 = 15
Number of pomegranates that she had at first
= 3 u
= 3 x 15
= 45
Answer(s): 45
