Kathy had an equal number of dates and apricots at first. She sold one-quarter of the apricots and bought another 50 dates. In the end, she had twice as many dates as apricots. Find the number of apricots she had at first.
| |
Apricots |
Dates |
| Before |
4 u |
6 u - 50 |
| Change |
- 1 u |
+ 50 |
| After |
3 u |
6 u |
The number of dates and apricots at first is the same.
6 u - 50 = 4 u
6 u - 4 u = 50
2 u = 50
1 u = 50 ÷ 2 = 25
Number of apricots that she had at first
= 4 u
= 4 x 25
= 100
Answer(s): 100
