Zoe had an equal number of apricots and kiwis at first. She sold one-quarter of the kiwis and bought another 75 apricots. In the end, she had thrice as many apricots as kiwis. Find the number of kiwis she had at first.
| |
Kiwis |
Apricots |
| Before |
4 u |
9 u - 75 |
| Change |
- 1 u |
+ 75 |
| After |
3 u |
9 u |
The number of apricots and kiwis at first is the same.
9 u - 75 = 4 u
9 u - 4 u = 75
5 u = 75
1 u = 75 ÷ 5 = 15
Number of kiwis that she had at first
= 4 u
= 4 x 15
= 60
Answer(s): 60
