Yen had an equal number of peaches and lemons at first. She sold half of the lemons and bought another 80 peaches. In the end, she had four times as many peaches as lemons. Find the number of lemons she had at first.
| |
Lemons |
Peaches |
| Before |
2 u |
4 u - 80 |
| Change |
- 1 u |
+ 80 |
| After |
1 u |
4 u |
The number of peaches and lemons at first is the same.
4 u - 80 = 2 u
4 u - 2 u = 80
2 u = 80
1 u = 80 ÷ 2 = 40
Number of lemons that she had at first
= 2 u
= 2 x 40
= 80
Answer(s): 80
