Sarah had an equal number of dates and kiwis at first. She sold one-quarter of the kiwis and bought another 40 dates. In the end, she had twice as many dates as kiwis. Find the number of kiwis she had at first.
| |
Kiwis |
Dates |
| Before |
4 u |
6 u - 40 |
| Change |
- 1 u |
+ 40 |
| After |
3 u |
6 u |
The number of dates and kiwis at first is the same.
6 u - 40 = 4 u
6 u - 4 u = 40
2 u = 40
1 u = 40 ÷ 2 = 20
Number of kiwis that she had at first
= 4 u
= 4 x 20
= 80
Answer(s): 80
