Hazel had an equal number of apricots and dates at first. She sold one-quarter of the dates and bought another 62 apricots. In the end, she had twice as many apricots as dates. Find the number of dates she had at first.
| |
Dates |
Apricots |
| Before |
4 u |
6 u - 62 |
| Change |
- 1 u |
+ 62 |
| After |
3 u |
6 u |
The number of apricots and dates at first is the same.
6 u - 62 = 4 u
6 u - 4 u = 62
2 u = 62
1 u = 62 ÷ 2 = 31
Number of dates that she had at first
= 4 u
= 4 x 31
= 124
Answer(s): 124
