Wesley had
110 as many coins as Ivan. Ivan had twice as many coins as David. If Wesley had 188 coins fewer than David,
- how many coins did Wesley have?
- how many coins did they have altogether?
(a)
Number of coins that Wesley had = 1 u
Number of coins that Ivan had = 10 u
Number of coins that David had = 10 u ÷ 2 = 5 u
Number of coins that Wesley had fewer than David
= 5 u - 1 u
= 4 u
4 u = 188
1 u = 188 ÷ 4 = 47
Number of coins that Wesley had
= 1 u
= 47
(b)
Total number of coins that they had
= 1 u + 10 u + 5 u
= 16 u
= 16 x 47
= 752
Answer(s): (a) 47; (b) 752
