Howard had
112 as many marbles as Peter. Peter had twice as many marbles as Pierre. If Howard had 165 marbles fewer than Pierre,
- how many marbles did Howard have?
- how many marbles did they have altogether?
(a)
Number of marbles that Howard had = 1 u
Number of marbles that Peter had = 12 u
Number of marbles that Pierre had = 12 u ÷ 2 = 6 u
Number of marbles that Howard had fewer than Pierre
= 6 u - 1 u
= 5 u
5 u = 165
1 u = 165 ÷ 5 = 33
Number of marbles that Howard had
= 1 u
= 33
(b)
Total number of marbles that they had
= 1 u + 12 u + 6 u
= 19 u
= 19 x 33
= 627
Answer(s): (a) 33; (b) 627
