Seth had
19 as many coins as Henry. Henry had thrice as many coins as Vincent. If Seth had 48 coins fewer than Vincent,
- how many coins did Seth have?
- how many coins did they have altogether?
(a)
Number of coins that Seth had = 1 u
Number of coins that Henry had = 9 u
Number of coins that Vincent had = 9 u ÷ 3 = 3 u
Number of coins that Seth had fewer than Vincent
= 3 u - 1 u
= 2 u
2 u = 48
1 u = 48 ÷ 2 = 24
Number of coins that Seth had
= 1 u
= 24
(b)
Total number of coins that they had
= 1 u + 9 u + 3 u
= 13 u
= 13 x 24
= 312
Answer(s): (a) 24; (b) 312
