Bobby had
19 as many coins as Peter. Peter had thrice as many coins as Wesley. If Bobby had 56 coins fewer than Wesley,
- how many coins did Bobby have?
- how many coins did they have altogether?
(a)
Number of coins that Bobby had = 1 u
Number of coins that Peter had = 9 u
Number of coins that Wesley had = 9 u ÷ 3 = 3 u
Number of coins that Bobby had fewer than Wesley
= 3 u - 1 u
= 2 u
2 u = 56
1 u = 56 ÷ 2 = 28
Number of coins that Bobby had
= 1 u
= 28
(b)
Total number of coins that they had
= 1 u + 9 u + 3 u
= 13 u
= 13 x 28
= 364
Answer(s): (a) 28; (b) 364
