Andy had
16 as many buttons as David. David had twice as many buttons as Sean. If Andy had 54 buttons fewer than Sean,
- how many buttons did Andy have?
- how many buttons did they have altogether?
(a)
Number of buttons that Andy had = 1 u
Number of buttons that David had = 6 u
Number of buttons that Sean had = 6 u ÷ 2 = 3 u
Number of buttons that Andy had fewer than Sean
= 3 u - 1 u
= 2 u
2 u = 54
1 u = 54 ÷ 2 = 27
Number of buttons that Andy had
= 1 u
= 27
(b)
Total number of buttons that they had
= 1 u + 6 u + 3 u
= 10 u
= 10 x 27
= 270
Answer(s): (a) 27; (b) 270
