Sam had
112 as many marbles as Lee. Lee had four times as many marbles as Riordan. If Sam had 76 marbles fewer than Riordan,
- how many marbles did Sam have?
- how many marbles did they have altogether?
(a)
Number of marbles that Sam had = 1 u
Number of marbles that Lee had = 12 u
Number of marbles that Riordan had = 12 u ÷ 4 = 3 u
Number of marbles that Sam had fewer than Riordan
= 3 u - 1 u
= 2 u
2 u = 76
1 u = 76 ÷ 2 = 38
Number of marbles that Sam had
= 1 u
= 38
(b)
Total number of marbles that they had
= 1 u + 12 u + 3 u
= 16 u
= 16 x 38
= 608
Answer(s): (a) 38; (b) 608
