Sean had
19 as many coins as Ahmad. Ahmad had thrice as many coins as Peter. If Sean had 76 coins fewer than Peter,
- how many coins did Sean have?
- how many coins did they have altogether?
(a)
Number of coins that Sean had = 1 u
Number of coins that Ahmad had = 9 u
Number of coins that Peter had = 9 u ÷ 3 = 3 u
Number of coins that Sean had fewer than Peter
= 3 u - 1 u
= 2 u
2 u = 76
1 u = 76 ÷ 2 = 38
Number of coins that Sean had
= 1 u
= 38
(b)
Total number of coins that they had
= 1 u + 9 u + 3 u
= 13 u
= 13 x 38
= 494
Answer(s): (a) 38; (b) 494
