Michael had
18 as many pens as Wesley. Wesley had twice as many pens as Will. If Michael had 114 pens fewer than Will,
- how many pens did Michael have?
- how many pens did they have altogether?
(a)
Number of pens that Michael had = 1 u
Number of pens that Wesley had = 8 u
Number of pens that Will had = 8 u ÷ 2 = 4 u
Number of pens that Michael had fewer than Will
= 4 u - 1 u
= 3 u
3 u = 114
1 u = 114 ÷ 3 = 38
Number of pens that Michael had
= 1 u
= 38
(b)
Total number of pens that they had
= 1 u + 8 u + 4 u
= 13 u
= 13 x 38
= 494
Answer(s): (a) 38; (b) 494
