Brandon had
19 as many cards as Bryan. Bryan had thrice as many cards as Sam. If Brandon had 80 cards fewer than Sam,
- how many cards did Brandon have?
- how many cards did they have altogether?
(a)
Number of cards that Brandon had = 1 u
Number of cards that Bryan had = 9 u
Number of cards that Sam had = 9 u ÷ 3 = 3 u
Number of cards that Brandon had fewer than Sam
= 3 u - 1 u
= 2 u
2 u = 80
1 u = 80 ÷ 2 = 40
Number of cards that Brandon had
= 1 u
= 40
(b)
Total number of cards that they had
= 1 u + 9 u + 3 u
= 13 u
= 13 x 40
= 520
Answer(s): (a) 40; (b) 520
