Ben had
110 as many buttons as Ken. Ken had twice as many buttons as Will. If Ben had 92 buttons fewer than Will,
- how many buttons did Ben have?
- how many buttons did they have altogether?
(a)
Number of buttons that Ben had = 1 u
Number of buttons that Ken had = 10 u
Number of buttons that Will had = 10 u ÷ 2 = 5 u
Number of buttons that Ben had fewer than Will
= 5 u - 1 u
= 4 u
4 u = 92
1 u = 92 ÷ 4 = 23
Number of buttons that Ben had
= 1 u
= 23
(b)
Total number of buttons that they had
= 1 u + 10 u + 5 u
= 16 u
= 16 x 23
= 368
Answer(s): (a) 23; (b) 368
