Eric had
112 as many coins as Mark. Mark had thrice as many coins as Cody. If Eric had 132 coins fewer than Cody,
- how many coins did Eric have?
- how many coins did they have altogether?
(a)
Number of coins that Eric had = 1 u
Number of coins that Mark had = 12 u
Number of coins that Cody had = 12 u ÷ 3 = 4 u
Number of coins that Eric had fewer than Cody
= 4 u - 1 u
= 3 u
3 u = 132
1 u = 132 ÷ 3 = 44
Number of coins that Eric had
= 1 u
= 44
(b)
Total number of coins that they had
= 1 u + 12 u + 4 u
= 17 u
= 17 x 44
= 748
Answer(s): (a) 44; (b) 748
