Peter had
19 as many erasers as Lee. Lee had thrice as many erasers as Vaidev. If Peter had 78 erasers fewer than Vaidev,
- how many erasers did Peter have?
- how many erasers did they have altogether?
(a)
Number of erasers that Peter had = 1 u
Number of erasers that Lee had = 9 u
Number of erasers that Vaidev had = 9 u ÷ 3 = 3 u
Number of erasers that Peter had fewer than Vaidev
= 3 u - 1 u
= 2 u
2 u = 78
1 u = 78 ÷ 2 = 39
Number of erasers that Peter had
= 1 u
= 39
(b)
Total number of erasers that they had
= 1 u + 9 u + 3 u
= 13 u
= 13 x 39
= 507
Answer(s): (a) 39; (b) 507
