Archie had
18 as many beads as Lee. Lee had twice as many beads as Paul. If Archie had 108 beads fewer than Paul,
- how many beads did Archie have?
- how many beads did they have altogether?
(a)
Number of beads that Archie had = 1 u
Number of beads that Lee had = 8 u
Number of beads that Paul had = 8 u ÷ 2 = 4 u
Number of beads that Archie had fewer than Paul
= 4 u - 1 u
= 3 u
3 u = 108
1 u = 108 ÷ 3 = 36
Number of beads that Archie had
= 1 u
= 36
(b)
Total number of beads that they had
= 1 u + 8 u + 4 u
= 13 u
= 13 x 36
= 468
Answer(s): (a) 36; (b) 468
