Ethan had
112 as many marbles as Luke. Luke had thrice as many marbles as Xavier. If Ethan had 69 marbles fewer than Xavier,
- how many marbles did Ethan have?
- how many marbles did they have altogether?
(a)
Number of marbles that Ethan had = 1 u
Number of marbles that Luke had = 12 u
Number of marbles that Xavier had = 12 u ÷ 3 = 4 u
Number of marbles that Ethan had fewer than Xavier
= 4 u - 1 u
= 3 u
3 u = 69
1 u = 69 ÷ 3 = 23
Number of marbles that Ethan had
= 1 u
= 23
(b)
Total number of marbles that they had
= 1 u + 12 u + 4 u
= 17 u
= 17 x 23
= 391
Answer(s): (a) 23; (b) 391
