Carl had some mangoes and chikoos. The number of mangoes and chikoos left were the same after Carl sold
12 of the mangoes and
57 of the chikoos. If he had 76 mangoes at first,
- How many mangoes were left?
- How many chikoos did Carl have at first?
| |
Mangoes |
Chikoos |
Before |
2x2 =
4 u |
7 u |
Change |
- 1x2 =
- 2 u |
- 5 u |
After |
1x2 =
2 u |
2 u |
(a)
Fraction of the mangoes left
= 1 -
12 =
12 Fraction of the chikoos left
= 1 -
57 =
27The number of mangoes and chikoos left were the same. Make the number of mangoes and chikoos left the same. LCM of 1 and 2 is 2.
Number of mangoes at first = 4 u
Number of chikoos at first = 7 u
4 u = 76
1 u = 76 ÷ 4 = 19
Number of mangoes left
= 2 u
= 2 x 19
= 38
(b)
Number of chikoos at first
= 7 u
= 7 x 19
= 133
Answer(s): (a) 38; (b) 133
