Cole had some kiwis and dragonfruits. The number of kiwis and dragonfruits left were the same after Cole sold
12 of the kiwis and
37 of the dragonfruits. If he had 96 kiwis at first,
- How many kiwis were left?
- How many dragonfruits did Cole have at first?
| |
Kiwis |
Dragonfruits |
Before |
2x4 =
8 u |
7 u |
Change |
- 1x4 =
- 4 u |
- 3 u |
After |
1x4 =
4 u |
4 u |
(a)
Fraction of the kiwis left
= 1 -
12 =
12 Fraction of the dragonfruits left
= 1 -
37 =
47The number of kiwis and dragonfruits left were the same. Make the number of kiwis and dragonfruits left the same. LCM of 1 and 4 is 4.
Number of kiwis at first = 8 u
Number of dragonfruits at first = 7 u
8 u = 96
1 u = 96 ÷ 8 = 12
Number of kiwis left
= 4 u
= 4 x 12
= 48
(b)
Number of dragonfruits at first
= 7 u
= 7 x 12
= 84
Answer(s): (a) 48; (b) 84
