Daniel had some lemons and pears. The number of lemons and pears left were the same after Daniel sold
15 of the lemons and
57 of the pears. If he had 60 lemons at first,
- How many lemons were left?
- How many pears did Daniel have at first?
| |
Lemons |
Pears |
Before |
5x1 =
5 u |
7 u |
Change |
- 1x1 =
- 4 u |
- 5 u |
After |
4x1 =
4 u |
2 u |
(a)
Fraction of the lemons left
= 1 -
15 =
45 Fraction of the pears left
= 1 -
57 =
27The number of lemons and pears left were the same. Make the number of lemons and pears left the same. LCM of 4 and 2 is 4.
Number of lemons at first = 5 u
Number of pears at first = 7 u
5 u = 60
1 u = 60 ÷ 5 = 12
Number of lemons left
= 2 u
= 2 x 12
= 24
(b)
Number of pears at first
= 7 u
= 7 x 12
= 84
Answer(s): (a) 24; (b) 84
