Dylan had some lemons and chikoos. The number of lemons and chikoos left were the same after Dylan sold
14 of the lemons and
35 of the chikoos. If he had 72 lemons at first,
- How many lemons were left?
- How many chikoos did Dylan have at first?
| |
Lemons |
Chikoos |
Before |
4x2 =
8 u |
5 u |
Change |
- 1x2 =
- 6 u |
- 3 u |
After |
3x2 =
6 u |
2 u |
(a)
Fraction of the lemons left
= 1 -
14 =
34 Fraction of the chikoos left
= 1 -
35 =
25The number of lemons and chikoos left were the same. Make the number of lemons and chikoos left the same. LCM of 3 and 2 is 6.
Number of lemons at first = 8 u
Number of chikoos at first = 5 u
8 u = 72
1 u = 72 ÷ 8 = 9
Number of lemons left
= 2 u
= 2 x 9
= 18
(b)
Number of chikoos at first
= 5 u
= 5 x 9
= 45
Answer(s): (a) 18; (b) 45
