Mark had some persimmons and mangoes. The number of persimmons and mangoes left were the same after Mark sold
12 of the persimmons and
37 of the mangoes. If he had 88 persimmons at first,
- How many persimmons were left?
- How many mangoes did Mark have at first?
| |
Persimmons |
Mangoes |
Before |
2x4 =
8 u |
7 u |
Change |
- 1x4 =
- 4 u |
- 3 u |
After |
1x4 =
4 u |
4 u |
(a)
Fraction of the persimmons left
= 1 -
12 =
12 Fraction of the mangoes left
= 1 -
37 =
47The number of persimmons and mangoes left were the same. Make the number of persimmons and mangoes left the same. LCM of 1 and 4 is 4.
Number of persimmons at first = 8 u
Number of mangoes at first = 7 u
8 u = 88
1 u = 88 ÷ 8 = 11
Number of persimmons left
= 4 u
= 4 x 11
= 44
(b)
Number of mangoes at first
= 7 u
= 7 x 11
= 77
Answer(s): (a) 44; (b) 77
